The North Carolina officer who fatally shot Keith Lamont Scott will not be charged

da keith lamont scott

Prosecutors will not charge the North Carolina police officer who fatally shot Keith Lamont Scott in September.

Mecklenburg County District Attorney Andrew Murray told media on Wednesday that Officer Brentley Vinson acted in self-defense when he shot Scott.

“It is my opinion that Officer Vinson acted lawfully when he shot Mr. Scott,” Murray said.

He said “all the credible evidence” shows Scott was armed and drew his gun when officers approached him, and ignored at least 10 commands to drop the gun when he stepped out of his SUV.

Scott’s DNA was also found on the grip of a gun recovered from the scene, Murray said.

“I know that some out there are going to be frustrated. I want everyone in this community to know that we meticulously, thoroughly reviewed all of the evidence in this case, made sure it was credible evidence in order to make the decision that we made today,” Murray said.

Join the conversation about this story »

NOW WATCH: ‘That hypocrisy is also real’ — Jon Stewart takes liberals to task for calling all Trump supporters racist

The North Carolina officer who fatally shot Keith Lamont Scott will not be charged syndicated from https://lawpallc.wordpress.com

Advertisements

Author: Tristan Fox

I love to spend my weekends roaming around my neighborhood with my bike. I am into promoting online websites related to lawsuits, law tips and lawfirms. In this way I am aiding them in pushing their contents in gaining more leverage for the power of internet for local lawfirms in and around my area.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s